Respuesta :
Answer:
[tex]{ \tt{(2x + y)( {n}^{2} - 3xy + {y}^{2} )}} \\ = { \tt{(2x {n}^{2} - 3 {x}^{2}y + 2x {y}^{2} + {n}^{2}y - 3x {y}^{2} + {y}^{3} )}} \\ = { \tt{ {y}^{3} - xy(y + 3x) + {n}^{2} y }}[/tex]
Hello!
(2x+y) (n2-3xy+y2)
2x* n²= 2xn²
2x* -3xy = -6x²y
2x* y² = 2xy²
y*n² = yn²
y*-3xy = -3xy²
y* y² = y³
=>
2xn²- 6x²y + 2xy² +yn²- 3xy² +y³
