Answer:
Explanation:
I willl go into a bit of detail on the haloform reaction. So the first few steps involve forming an enolate using the base, typically NaOH. THe enolate and go on to do alpha halogenation 3 times. After that, is leaves a trisubstituted alpha methyl carbon with a specific halogen. This is a good leaving group in itself and can carbonyl nucleophillic substitution and turn into a carboxylic acid with a CHZ3- byproduct where Z represents a halogen.
