Answer:
[tex](x+4)^2 - 11 = 0\\[/tex]
a = 4
b = -11
Step-by-step explanation:
[tex]x^{2} +8x+5\\[/tex]
use the complete the square method:
[tex]x^{2} +8x+5=0\\x^{2} +8x = -5\\\\(x+4)^{2} = x^2 + 8x + 16\\\\x^2 + 8x + 16 = -5 + 16\\[/tex]
we completed the square of x^2 + 8x + ... which is x^2 + 8x + 16 using (x+4)^2
we added 16 to both sides because whatever you do to one side, you have to do to the other:
[tex]x^{2} +8x+16 = 11\\(x+4)^2 = 11\\(x+4)^2 - 11 =0[/tex]
