Respuesta :

sqdancefan

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Answer:

  (b)  (x -y)/(x +2y)^2

Step-by-step explanation:

You want the quotient ...

  [tex]\dfrac{\left(\dfrac{x^2-4xy+3y^2}{x+2y}\right)}{x^2 -xy-6y^2}=\dfrac{(x-3y)(x-y)}{(x+2y)(x-3y)(x+2y)}=\boxed{\dfrac{x-y}{(x+2y)^2}}[/tex]

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