How many moles of O₂ would be required to generate 13.0 mol of NO₂ in the reaction below assuming the reaction has only 83.9% yield?
2 NO (g) + O₂ (g) → 2 NO₂ (g)

Respuesta :

Answer:

I cant tell you its not 10.01

Explanation:

9+10=21

Mass of O2+ 2NO

add in the quantum flux making the radioactive spider ∪Δ

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