9514 1404 393
Answer:
13 units
Step-by-step explanation:
The distance d between the point (x, y) and the line ax+by+c=0 is ...
d = |ax +by +c|/√(a² +b²)
For the given point and line, the distance is ...
d = |5·0 -12·0 -169|/√(5² +(-12)²) = 169/√169 = √169
d = 13
The distance between the line and the origin is 13 units.
