Answer:
1/36
Step-by-step explanation:
I see that the functional values must be the product
3^a × 2^b
a starts at 0 (3⁰ = 1), and b starts at -2 (2^-2 = 1/4).
so, bringing x in this means
f(x) = 3^x × 2^(x-2)
0 and 2 are two apart.
so,
f(0)/f(2) = (3⁰×2^-2)/(3²×2⁰) = 1/4 / 9 = 1/36
f(1)/f(3) = 3/2 / 54 = 3/108 = 1/36
f(2)/f(4) = 9 / 324 = 1/36
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