The second term of the progression will be 22
Given the following parameters
ai+1= 3ai+1
a0=2
If i = 0
[tex]a_{i+1}= 3a_i}+1 \\a_{0+1}=3a_{0}+1}\\a_1=3(2)+ 1\\a_1 = 7[/tex]
Similarly to get the second term a2, when i = 1
[tex]a_{i+1}= 3a_i}+1 \\a_{1+1}=3a_{1}+1}\\a_2=3(7)+ 1\\a_2 = 22[/tex]
Hence the second term of the progression will be 22
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