Answer:
[tex]\frac{11}{16}[/tex]
Step-by-step explanation:
We know
[tex]\\ \sf\longmapsto sin\Theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]
Now
[tex]\\ \sf\longmapsto sinA=\dfrac{BC}{AC}[/tex]
[tex]\\ \sf\longmapsto sinA=\dfrac{11}{16}[/tex]
