Answer:
[tex]\huge\boxed{\sf 41,\ 43, \ 45}[/tex]
Step-by-step explanation:
Let the three consecutive integers be x, x + 2 and x + 4
So, the given condition is:
x + x + 2 + x + 4 = 129
3x + 6 = 129
Subtract 6 to both sides
3x = 129 - 6
3x = 123
Divide 3 to both sides
x = 123/3
x = 41
So, the integers are:
x = 41
x + 2 = 41 + 2 = 43
x + 4 = 41 + 4 = 45
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
