73.9m/s (1dp)
1) list everything that you are given using suvat, where s is distance, u is initial velocity(speed), v is final velocity(speed), a is acceleration and t is time
s = 430m
u = 27 m/s
v = ? (we need to work out)
a = 5.5m/s^2
t = (we are not given this value)
2) use an equation that doesn't involve the time
[tex] {v}^{2} = u {}^{2} + 2as[/tex]
3) input the values that we have
[tex] {v}^{2} = ( {27})^{2} + 2(5.5)(430)[/tex]
[tex]v {}^{2} = 5459[/tex]
[tex]v = \sqrt{5459} = 73.9[/tex]
so the answer is 73.9m/s to 1dp
