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abidemiokin

The quadratic equation has two solutions if b^2 - 4ac > 0

Given the equation ax^4 + bx^2 + c=0

  • Let P = x^2

Substitute into the formula to have:

  • a(x^2)^2 + bx^2 + c =0

The equation becomes aP^2 + bP + c = 0

For us to have a unique solution, the discriminant b^2 - 4ac must be greater than zero. Hence the quadratic equation has two solutions if b^2 - 4ac > 0

learn more on discriminant here; https://brainly.com/question/1537997

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