kirbygabriell kirbygabriell
  • 19-02-2022
  • Mathematics
contestada

Francium has a decay rate of 50% every 22 minutes. How much of an initial amount of 4.8 grams would be left after 88 minutes?
t=88/22=4A=Aoe^-kt

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SpiritInly
SpiritInly SpiritInly
  • 19-02-2022

Answer:

0.65g

Step-by-step explanation:

Decay rate = 50%

Decay rate = 0.5

[tex]A = Aoe {}^{ - kt} [/tex]

where Ao = initial amount at start, k = rate of decay or growth, t = time, e = euler's number and A = value at time 't'

Ao = 4.8

t = 88/44 = 4

k = 0.5

substitute these values in the equation

[tex]A = 4.8e {}^{ - 0.5 \times 4} [/tex]

[tex]A = 0.6496[/tex]

[tex]A = 0.65 \: (2dp)[/tex]

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