Answer:
[tex]\dfrac25[/tex]
Step-by-step explanation:
[tex]y \propto \dfrac{1}{x^2} \implies y=\dfrac{k}{x^2} \ \ \ \textsf{where k is some constant}[/tex]
when y = 10 and x =2:
[tex]\implies 10=\dfrac{k}{2^2}[/tex]
[tex]\implies k=40[/tex]
Therefore,
[tex]\implies y=\dfrac{40}{x^2}[/tex]
when x=10:
[tex]\implies y=\dfrac{40}{10^2}=\dfrac{40}{100}=\dfrac25[/tex]
