Answer:
x = [tex]\sqrt{22}[/tex]
Step-by-step explanation:
the 2 legs are congruent
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then
x² = ([tex]\sqrt{11}[/tex] )² + ([tex]\sqrt{11}[/tex] )² = 11 + 11 = 22 ( take square root of both sides )
x = [tex]\sqrt{22}[/tex]
