Answer:
I believe it would be [tex]a_{n} = -4 *(-2)^{n-1}; -64[/tex] aka the second option.
Step-by-step explanation:
In this example we have [tex]a_{1} = -4, r =2, n=5\\[/tex]
to find [tex]a_{5}[/tex] we use formula [tex]a_{n}=a_{1} * r^{n-1}[/tex]
. After substituting these values to above formula, we obtain:
[tex]a_{n}=a_{1} * r^{n-1}\\a_{5} = -4* (-2)^{5-1}\\ a_{5} =-4 * 16\\a_{5} =-64[/tex]
hope this was helpful :)
