Answer:
distance = 27x³ + 9x² - 3x , time = 3x ,
rate =?
[tex]distance = rate \times time \\ \\ rate = \frac{distance}{time} \\ \\ r = \frac{d}{t} \\ \\ r = \frac{27 {x}^{3} + 9 {x}^{2} - 3x}{3x} \\ \\ r = \frac{3x(9 {x}^{2} + 3x - 1) }{3x} \\ \\ r = 9 {x}^{2} + 3x - 1[/tex]
So; The rate of the car equal (9x²+3x-1)
