tan(-180°+x).cosx.cos24°÷cos(90°-x).sin66°

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16-04-2022
Mathematics

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tan(-180°+x).cosx.cos24°÷cos(90°-x).sin66°

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602654 602654 · Answer 1 · 2022-04-16T18:44:28+02:00

602654 602654

16-04-2022

Answer to Solved - d) - 1 - cos²x sin (900° - x) tan (-180° + x). cos. ... cos²x sin (900° - x) tan (-180° + x). cos x. cos 24° COS cos (90° - x). sin 66° ...

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tan(-180°+x).cosx.cos24°÷cos(90°-x).sin66°​

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tan(-180°+x).cosx.cos24°÷cos(90°-x).sin66°