Answer:
8/(u^2y^3) -19/3
Step-by-step explanation:
The relevant rules of exponents are ...
(a^b)/(a^c) = 1/a^(c-b)
a^0 = 1
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Your expression can be simplified like this:
[tex]\dfrac{-24uy^2+19u^3y^5}{-3u^3y^5}=\dfrac{24uy^2}{3u^3y^5}-\dfrac{19u^3y^5}{3u^3y^5}=\boxed{\dfrac{8}{u^2y^3}-\dfrac{19}{3}}[/tex]
