obiegremillion obiegremillion
  • 20-04-2022
  • Mathematics
contestada

Find x, where x^6 = 9^-3 and x > 0.
x > 0


bit rusty with exponents so could I have some help?

Respuesta :

jdoe0001 jdoe0001
  • 20-04-2022

[tex]~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x^6~~ = ~~9^{-3}\implies x^6~~ = ~~(3^2)^{-3}\implies x^6~~ = ~~3^{-6} \\\\\\ x^6~~ = ~~(3^{-1})^6\implies x=3^{-1}\implies x=\cfrac{1}{3^1}\implies x=\cfrac{1}{3}[/tex]

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