[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: a = \pi {r}^{2} [/tex]
- where, r = d/2 = 6/2 = 3 ft
[tex]\qquad \sf \dashrightarrow \: a = 3.14 \times {3}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \: a = 3.14 \times 9[/tex]
[tex]\qquad \sf \dashrightarrow \: a = 13.26 \: \: ft {}^{2} [/tex]
