Answer:
[tex]x = \pm 2\sqrt3[/tex]
Step-by-step explanation:
Hello!
Let's use the square root property to solve this question
Solve:
- [tex]x^2 = 12[/tex]
- [tex]\sqrt{x^2} = \sqrt{12}[/tex]
- [tex]x = \pm\sqrt{12}[/tex]
- [tex]x = \pm \sqrt{4 * 3}[/tex]
- [tex]x = \pm 2\sqrt3[/tex]
The answer is option A: x = ±2√3
