The value of x = ±[tex]\sqrt{64-y} /4[/tex]
Given: y= 64 - 16[tex]x^{2}[/tex]
⇒ 64 - 16 [tex]x^{2}[/tex] - y = 0
- 16 [tex]x^{2}[/tex] +64 - y = 0
x= 0 ± √(-4)(-16)(64-y)/2(-16)
x= 0 ± √64(64-y)/2(-16)
x= 0 ± 8√(64-y)/-32
x= 8√(64-y)/-32
⇒The value of x = ±[tex]\sqrt{64-y} /4[/tex]
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