The inverse of the equation y = x² - 4, x≤ 0 is [tex]y = \sqrt{x + 4[/tex]
How to determine the inverse of the equation?
The equation is given as:
y = x² - 4, x≤ 0
Swap the x and y values
x = y² - 4
Add 4 to both sides
y² = x + 4
Take the square root of both sides
[tex]y = \sqrt{x + 4[/tex]
Hence, the inverse of the equation y = x² - 4, x≤ 0 is [tex]y = \sqrt{x + 4[/tex]
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