Respuesta :

devishri1977

Answer:

[tex]\sf Sin \ S = \dfrac{2}{9}[/tex]

Step-by-step explanation:

Trigonometry ratios:

 [tex]\sf \boxed{\bf Sin \ S = \dfrac{opposite \ side \ of \ \angle S}{hypotenuse}}[/tex]

             [tex]\sf = \dfrac{RQ}{SQ}\\\\= \dfrac{2}{9}[/tex]