TrucerZ3674 TrucerZ3674
  • 19-07-2022
  • Mathematics
contestada

Find the equation of the line perpendicular to 2x+3y-6=0 and passing through (-1,1)

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Medunno13
Medunno13 Medunno13
  • 25-07-2022

Answer: [tex]y-1=\frac{3}{2}(x+1)[/tex]

Step-by-step explanation:

[tex]2x+3y-6=0\\\\3y=-2x+6\\\\y=-\frac{2}{3}x+2[/tex]

So, the slope of the given line is -2/3, meaning the slope of the line we want to find is 3/2.

Substituting into point-slope form, we get the equation of the line is

[tex]y-1=\frac{3}{2}(x+1)[/tex]

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