The factored inequality is [tex]x^2-3x+6\geq 0[/tex]
Factoring Inequalities
The given inequality is:
[tex]-x^2+3x-6\leq 0[/tex]
This can be further simplified as:
[tex]-(x^2-3x+6)\leq 0[/tex]
The inequality can be re-written as:
[tex]x^2-3x+6\geq 0[/tex]
Since the question does not state that we should solve the inequality, the simplest we can get after factoring is [tex]x^2-3x+6\geq 0[/tex]
Learn more on factoring of inequality here: https://brainly.com/question/16789297
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