contestada

A sample of an unknown substance has a mass of 0. 465 kg. If 3,000. 0 j of heat is required to heat the substance from 50. 0°c to 100. 0°c, what is the specific heat of the substance? use q equals m c subscript p delta t.

Respuesta :

Answer:

.129 J / g-C

Explanation:

specific heat =  J / g-°C

                     = 3000 J / ( 465 g  * 50C ) =.129 J /g-C