Respuesta :

Answer:

B

Step-by-step explanation:

[tex]\frac{x}{x-3}[/tex] × [tex]\frac{2x}{x+5}[/tex] ( no factors cancel on numerator / denominator )

= [tex]\frac{x(2x)}{(x-3)(x+5)}[/tex]

= [tex]\frac{2x^2}{x^2+2x-15}[/tex]

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