The values of f⁻¹(f(6.022)) is 6.022 and f⁻¹(10) + f(-6) is 4
How to evaluate the function?
As a general rule;
f⁻¹(f(x)) = x
This means that:
f⁻¹(f(6.022)) = 6.022
Also, we have:
f⁻¹(10) + f(-6)
From the table of values, we have:
f⁻¹(10) = -6 and f(-6) =10
So, we have:
f⁻¹(10) + f(-6) = -6 + 10
Evaluate
f⁻¹(10) + f(-6) = 4
Hence, the values of f⁻¹(f(6.022)) is 6.022 and f⁻¹(10) + f(-6) is 4
Read more about inverse functions at:
https://brainly.com/question/2541698
#SPJ1
