Area must the plates have is 1.26 x 10^-16 m^2
Given:
The capacitance of the parallel plate capacitor:
= 0.40F
The separation between the plates = 2.8-mm
To Find:
area of plates
Solution:
The capacitance of the parallel plate capacitor can be expressed as:
C = ε0*A/d
A = Cd/ε0
A = 0.40 x 0.0028/8.85*10^-12
A = 1.26 x 10^-16 m^2
Hence, area must the plates have is 1.26 x 10^-16 m^2
Learn more about Parallel plates here
https://brainly.com/question/26871451
#SPJ4
