Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I?

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kaliom12 kaliom12

21-02-2017
Mathematics

contestada

Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I?

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ahonyek ahonyek · Answer 1 · 2017-02-21T17:37:48+01:00

ahonyek ahonyek

21-02-2017

2=2
3=3
4=2*2
6=2*3
8=2*2*2
12=2*2*3
16=2*2*2*2
24=2*2*2*3
32=2*2*2*2*2
48=2*2*2*2*3

This is called the prime factors of these numbers. As you can see 3 only appears once for a single number. The maximum number of 2s is 5.
Thus the solution is 2*2*2*2*2*3=96

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Аноним Аноним · Answer 2 · 2017-02-21T22:53:20+01:00

Аноним Аноним

21-02-2017

2=2
3=3
4=2*2
6=2*3
8=2*2*2
12=2*2*3
16=2*2*2*2
24=2*2*2*3
32=2*2*2*2*2
48=2*2*2*2*3

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