what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?

Question

18-11-2022
Chemistry

contestada

what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?

Respuesta :

Otras preguntas

An average person can type 40 words per minute. In order to find the probability that a person will type more than 100 words in 3 minutes using the Poisson dist

Walter Cronkite ________. Select all that apply. a. turned against the war after the Tet Offensive b. reported that the United States ought to negotiate an end

Which of the following sentences is accurate? a. PDF stands for "Proofreading Direct Files." b. PDF files cannot be edited. c. Businesses are using PDF files mo

The equation to calculate density is D = m/v. For a liquid substance, which item increases as heatis applied? density O mass O volume Odensity and volume

A researcher plans to evaluate a new reading program by measuring students’ reading skill before and after the program begins. If all the students have high rea

Solve equation then graph -25x+y=65

A survey was administered to high school seniors in Anytown. According to the survey results, fewer than 0.5% of the students drove drunk in the previous 3 mont

A high-performance sports car can go from 0 to 100 mph in 5.8 s. (Assume the car travels in the positive direction. Indicate the direction with the sign of your

Based on the mole ratios of the substances in a chemical reaction shown, which is the correct equation for the chemical reaction?

Positive electric charge Q is distributed uniformly throughout the volume of an insulating sphere with radius R. Find the magnitude of the electric field at a p

contexto1220 contexto1220 · Answer 1 · 2022-11-22T10:20:43+01:00

A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is ([tex]M1V1 = M2V2[/tex]).

Utilize the titration method of [tex]M1V1 = M2V2[/tex] in view that we're given the concentrations of every compound and the quantity of [tex]KOH[/tex]. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.

M1 = initial mass
V1= initial volume
M2 = final mass
V2= final volume

[tex](M1V1 = M2V2)[/tex]
(0.138)(V1) = (0.205)x(26.0)
V2=(0.205)x(26.0)\ 0.138
V2 = 47.10 M/L
The final value of Volume needed for neutralization of nitric acid solution is V2 = 47.10 M/L