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The probability that the delegates arrives by aur is less then 7 is 0.98.
Given that the probability that a delegate to a certain convention arrived by air = 0.4
the probability that a delegate to a certain convention arrived by bus = 0.2
the probability that a delegate to a certain convention arrived by automobile = 0.3
the probability that a delegate to a certain convention arrived by train = 0.1
We have to calculate the probability that the number of delegates arrived by air is less than 7
When 7 delegates arrives by air and 2 by bus
=(0.4^7)*(0.2^2)*(FACT(9)/(FACT(7)*FACT(2))
When 7 delegates arrives by air and 2 by automobile = (0.4^7)*(0.3^2)*(FACT(9)/(FACT(7)*FACT(2))
When 7 delegates arrives by air and 2 by train = (0.4^7)*(0.1^2)*(FACT(9)/(FACT(7)*FACT(2))
When 8 delegates arrives by air and 1 by bus = (0.4^8)*(0.2^1)*(FACT(9)/(FACT(8)*FACT(1))
When 8 delegates arrives by air and 1 by automobile = (0.4^8)*(0.3^1)*(FACT(9)/(FACT(8)*FACT(1))
When 8 delegates arrives by air and 1 by train = (0.4^8)*(0.1^1)*(FACT(9)/(FACT(8)*FACT(1))
When all 9 delegates arrives by air = (0.4^9)*(FACT(9)/(FACT(9)
On calculation We get 1- 0.02 = 0.98
the probability that delagates arrives by air is less then 7 is 0.98
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Given that the probability that a delegate to a certain convention arrived by air = 0.4
the probability that a delegate to a certain convention arrived by bus = 0.2
the probability that a delegate to a certain convention arrived by automobile = 0.3
the probability that a delegate to a certain convention arrived by train = 0.1
We have to calculate the probability that the number of delegates arrived by air is less than 7
When 7 delegates arrives by air and 2 by bus
=(0.4^7)*(0.2^2)*(FACT(9)/(FACT(7)*FACT(2))
When 7 delegates arrives by air and 2 by automobile = (0.4^7)*(0.3^2)*(FACT(9)/(FACT(7)*FACT(2))
When 7 delegates arrives by air and 2 by train = (0.4^7)*(0.1^2)*(FACT(9)/(FACT(7)*FACT(2))
When 8 delegates arrives by air and 1 by bus = (0.4^8)*(0.2^1)*(FACT(9)/(FACT(8)*FACT(1))
When 8 delegates arrives by air and 1 by automobile = (0.4^8)*(0.3^1)*(FACT(9)/(FACT(8)*FACT(1))
When 8 delegates arrives by air and 1 by train = (0.4^8)*(0.1^1)*(FACT(9)/(FACT(8)*FACT(1))
When all 9 delegates arrives by air = (0.4^9)*(FACT(9)/(FACT(9)
On calculation We get 1- 0.02 = 0.98
the probability that delagates arrives by air is less then 7 is 0.98
To know more about probability follow the given link:
https://brainly.com/question/24756209
#SPJ4