Respuesta :

irspow
x^3−x^2−12x=0

x(x^2-x-12)=0

x(x^2-4x+3x-12)=0

x(x(x-4)+3(x-4))=0

x(x+3)(x-4)=0

So the "zeros" are:

x=(-3,0,4)

Answer:

-3,0,4

Step-by-step explanation:

This is what i got