The area of the sector will be 9π m².
We know, area of circle is given as πr², where r is the radius of the circle.
Here Area of circle,C = 72π m²
Area of a sector that subtends an angle 45° at the center (the area shaded in yellow color) is given as:
A = 72[tex] \pi m^{2} [/tex]×[tex] \frac{45}{360} [/tex]
⇒ A = 45× [tex] \frac{1}{5} [/tex]π m².
⇒ A = 9π m².
