Respuesta :

mrmeanmugg
The second option is what I would choose bro
WojtekR
We use:

[tex]a^2-b^2=(a-b)(a+b)[/tex]

so:

[tex]16r^2- 36t^2=(4r)^2-(6t)^2=\boxed{(4r-6t)(4r+6t)} [/tex]

Answer D.

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