Since the x coefficients are + and - 12 T
I would use elimination method to solve this system.
-12x-5y = 40
12x -11y =88
Add the equations.
-16y = 128
Divide both sides by-16
y = -8
Plug -8 back into either equation and solve for x.
-12x -5(-8) = 40
-12x + 40 = 40
Subtract 40 from both sides.
-12x = 0
Divide both sides by-12
x = 0
(0, -8)
