tuckertrash25
tuckertrash25 tuckertrash25
  • 18-05-2017
  • Mathematics
contestada

What is the distance between points (−2, 8) and (6, −2)? Round to the nearest tenth of a unit.

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evanman59 evanman59
  • 18-05-2017
If you make a right triangle from one coordinate to the other your side lengths would be 8 and 10
using the pythagorean theorem you add 64 and 100 then find its square root
Your answer is 12.8
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mjankiewicz
mjankiewicz mjankiewicz
  • 18-05-2017

[tex]|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}[/tex]Formula

[tex]A=(x_A,y_A) = (-2,8) \\\\ B=(x_B,y_B)=(6,-2)[/tex]

[tex]|AB|=\sqrt{(6+2)^2+(-2-8)^2}=\\\\=\sqrt{8^2+(-10)^2}=\\\\ =\sqrt{164}\approx12.8[/tex]


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