First, we calculate the moles of ammonium nitrate: Moles = mass / molecular mass Moles = 86.5 / 80 Moles = 1.08
From the equation, it is visible that the molar ratio between ammonium nitrate and dinitrogen monoxide is 1 : 1. The moles of dinitrogen monoxide formed will be: 1.08 moles
Next, we may apply the ideal gas law equation to find the volume: PV = nRT V = nRT/P V = (1.08 * 0.082 * 328)/1.28 V = 22.69 liters
22.7 liters of dinitrogen monoxide will be produced
