Answer:
[tex]-48r^{2} -10r+3[/tex]
Step-by-step explanation:
we have
[tex](6r-1)(-8r-3)[/tex]
Applying distributive property
[tex](6r-1)(-8r-3)=6r(-8r)+6r(-3)+1(8r)+1(3)\\ \\=-48r^{2} -18r+8r+3\\ \\=-48r^{2} -10r+3[/tex]
