Respuesta :

mergl
(1/4ab)^(-2)
(1/4)^(-2)(a)^(-2)(b)^(-2)
(4)^(2)(1/a(^2))(1/b(^2))
16/((a^2)(b^2))
calculista

Answer:

[tex]\frac{16}{a^{2}b^{2}}[/tex]

Step-by-step explanation:

we have

[tex](\frac{1}{4}ab)^{-2}[/tex]

Remember that

[tex](\frac{a}{b})^{-x}=(\frac{b}{a})^{x}=\frac{b^{x}}{a^{x}}[/tex]

so

[tex](\frac{1}{4}ab)^{-2}=(\frac{4}{ab})^{2}=\frac{16}{a^{2}b^{2}}[/tex]