max236524
max236524 max236524
  • 17-07-2017
  • Mathematics
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Please help ASAP.….......

Please help ASAP class=

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zrh2sfo
zrh2sfo zrh2sfo
  • 18-07-2017
The volume is 408.40704496667 in²
The equation for a circular truncated code is: 
V=1/3π(r1²+r1r2+r2²)h
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