Respuesta :
Answer:
The solution is x = 2 or x = 3
Step-by-step explanation:
we have to find the solution of the equation
[tex] x=2+\sqrt{(x-2)}[/tex]
[tex]x=2+\sqrt{(x-2)}\\ \\x-2=\sqrt{x-2}\\\\\text{Squaring on both sides }\\\\(x-2)^2=x-2\\\\x^2+4-4x=x-2\\\\x^2-5x+6=0\\\\x^2-2x-3x+6=0\\\\x(x-2)-3(x-2)=0\\\\(x-2)(x-3)=0\\\\x=2\text{ or }x=3[/tex]
Hence, correct option is x = 2 or x = 3
