For the following reaction, 3.83 grams of hydrochloric acid are mixed with excess iron(III) oxide. The reaction yields 0.778 grams of water.
(HCl(aq) + Fe₂O₃(s) →)
a) (H₂O(l) + FeCl₂(aq))
b) (H₂O(l) + Fe₂Cl₃(aq))
c) (H₂O(g) + FeCl₃(aq))
d) (H₂O(l) + Fe₃Cl₄(aq))