Answer:
[tex]c = 1\text{ or }c = -\frac{2}{3}[/tex]
Step-by-step explanation:
Here, the given equation,
|2c+8|=|10c|
( since, |x| = x if x > 0 and |x| = -x if x < 0 )
⇒ 2c + 8 = ± 10c
⇒ 8 = -2c ± 10c
⇒ 8 = -2c + 10c or 8 = -2c - 10c
⇒ 8 = 8c or 8 = -12c
[tex]\implies c = 1\text{ or }c = \frac{8}{-12}=-\frac{2}{3}[/tex]
