Answer:
Step-by-step explanation:
From the given triangle DEF, we have
[tex](EF)^{2}=(ED)^{2}+(DF)^{2}[/tex]
[tex](10)^{2}=(8)^{2}+(DF)^{2}[/tex]
[tex]100-64=(DF)^2[/tex]
[tex]DF=6[/tex]
Now, we know that SinE=[tex]\frac{Perpendicular}{Hypotenuse}[/tex], thus
[tex]SinE=\frac{DF}{EF}[/tex]
[tex]SinE=\frac{6}{10}=\frac{3}{5}[/tex]
Therefore, the value of SinE is [tex]\frac{3}{5}[/tex].
