a) m=months passed
f(m)=2*1.05^m
b) 8 weeks=2 months
f(2)=2*1.05^2=2.205
so essentially still 2
c)100=2*1.05^m
50=1.05^m
log1.05(50)=m
log(50)/log(1.05)=m=80.18
so after 80 months she will have nearly 100 cats (99.12), but will only break through the 100 with her 81st month
