Respuesta :

caylus
Hello,

[tex] \dfrac{1+tan(x)}{1+cotg(x)} = \dfrac{1+ \frac{sin(x)}{cos(x)} }{1+ \frac{cos(x)}{sin(x)}} \\\\ = \dfrac{cos(x)+sin(x)}{cos(x)*( \frac{sin(x)+cos(x)}{sin(x)} } )\\\\ = \dfrac{sin(x)}{cos(x)} \\\\ \boxed{=tan(x)}\\\\ [/tex]