Answer:
The answer is the option C
cube root of [tex]16[/tex]
Step-by-step explanation:
Remember that
[tex]a^{\frac{x}{y}} =\sqrt[y]{a^{x}}[/tex]
in this problem we have
[tex]a^{\frac{x}{y}}=2^{\frac{4}{3}}[/tex]
therefore
[tex]2^{\frac{4}{3}} =\sqrt[3]{2^{4}}=\sqrt[3]{16}[/tex]
